Herbistry420
hybrid

Garlic Sherbert #1 Flower M50

Limonene-dominant
THC
23.2–31.3%
Dominant Terpene
Limonene

About

Garlic Sherbert #1 Flower M50 is a hybrid cannabis strain. Lab samples test between 23.2% and 31.3% THC, with limonene (0.43%) as the dominant terpene.

Why does Garlic Sherbert #1 Flower M50 have these effects?

Garlic Sherbert #1 Flower M50's effects are driven by its dominant limonene (0.43%), known for mood elevation and stress relief, combined with caryophyllene (0.29%), one of the few terpenes that binds directly to CB2 cannabinoid receptors.

Strain Profile

Energy
CalmingEnergizing
Potency
Low THCHigh THC

May Help With

Inflammation100%

Caryophyllene has strong anti-inflammatory properties

Stress81%

Linalool has calming, stress-relieving properties

Pain80%

Caryophyllene binds to CB2 receptors for pain relief

Anxiety71%

Linalool is known for anti-anxiety effects

Based on terpene research and reported effects. Not medical advice. Consult a healthcare professional for medical decisions.

Quick Info

Type
hybrid
Breeder
Not verified
THC
23.2–31.3%
Chemotype
Limonene-dominant

What is Limonene?

Citrus-scented terpene found in lemon rinds, orange peels, and juniper.

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About Garlic Sherbert #1 Flower M50

Is Garlic Sherbert #1 Flower M50 indica or sativa?
Garlic Sherbert #1 Flower M50 is a hybrid cannabis strain. Hybrids combine characteristics of both indica and sativa genetics.
What is the THC content of Garlic Sherbert #1 Flower M50?
Garlic Sherbert #1 Flower M50 typically tests at 23.2% to 31.3% THC. This is considered a high-potency strain, so start with a low dose if you are new to it.
What terpenes are in Garlic Sherbert #1 Flower M50?
The dominant terpenes in Garlic Sherbert #1 Flower M50 are Limonene, Caryophyllene, Linalool. Terpenes influence the aroma, flavor, and effects of a cannabis strain.